2 NaOH + CuBr₂ → Cu(OH)₂ + 2 NaBr
Här är en uppdelning av reaktionen:
* reaktanter:
* Natriumhydroxid (NaOH) är en stark bas.
* Copper bromide (CuBr₂) is a soluble ionic compound.
* Produkter:
* Copper(II) hydroxide (Cu(OH)₂) is a blue-green precipitate that forms.
* Sodium bromide (NaBr) is a soluble ionic compound that remains in solution.
The reaction is a double displacement reaction. This means that the positive and negative ions of the reactants switch places to form the products.
Here's how to balance the reaction:
1. Start with the unbalanced equation: NaOH + CuBr₂ → Cu(OH)₂ + NaBr
2. Count the number of atoms of each element on both sides:
* na: 1 till vänster, 1 till höger
* o: 1 till vänster, 2 till höger
* h: 1 till vänster, 2 till höger
* cu: 1 till vänster, 1 till höger
* br: 2 on the left, 1 on the right
3. Adjust the coefficients in front of each compound to balance the number of atoms:
* Place a "2" in front of NaOH and NaBr to balance the Na, O, H, and Br atoms.
The balanced equation is 2 NaOH + CuBr₂ → Cu(OH)₂ + 2 NaBr